What is the output of the following snippet? #include <iostream> using namespace std; int main(){ int i = 1; if (--i == 1) { cout << i; } else { cout << --i; } return 0; } 1 --1 -1 0

The output of the given code snippet will be -1.

Here's the step by step explanation:

1. The variable i is initialized with the value 1.

2. In the if condition, --i is used which is a pre-decrement operation. This means that the value of i is decremented by 1 before the comparison. So, i becomes 0.

3. The if condition checks if i is equal to 1. Since i is 0, the condition is false. Therefore, the program goes to the else block.

4. In the else block, cout << --i; is executed. Again, --i is a pre-decrement operation. So, i is decremented by 1 again and becomes -1.

5. The value of i (-1) is printed.

So, the output is -1.