The frequency of a wave can be determined from its wave equation, which in this case is given as z(y, t) = 1.50 cm sin(1,250 rad/s t + 10.0 m−1 y).

The general form of a wave equation is z(y, t) = A sin(ωt + ky), where ω is the angular frequency of the wave.

From the given wave equation, we can see that the angular frequency ω is 1,250 rad/s.

The frequency f of the wave is related to the angular frequency by the equation f = ω / 2π.

Substituting ω = 1,250 rad/s into this equation gives f = 1,250 / 2π = 198.94 Hz.

Therefore, the frequency of the vibration of the wave is approximately 199 Hz.

Question

The frequency of a wave can be determined from its wave equation, which in this case is given as z(y, t) = 1.50 cm sin(1,250 rad/s t + 10.0 m−1 y).

The general form of a wave equation is z(y, t) = A sin(ωt + ky), where ω is the angular frequency of the wave.

From the given wave equation, we can see that the angular frequency ω is 1,250 rad/s.

The frequency f of the wave is related to the angular frequency by the equation f = ω / 2π.

Substituting ω = 1,250 rad/s into this equation gives f = 1,250 / 2π = 198.94 Hz.

Therefore, the frequency of the vibration of the wave is approximately 199 Hz.

Knowee AI · Accepted Answer

The frequency of a wave can be determined from its wave equation, which in this case is given as z(y, t) = 1.50 cm sin(1,250 rad/s t + 10.0 m−1 y).

The general form of a wave equation is z(y, t) = A sin(ωt + ky), where ω is the angular frequency of the wave.

From the given wave equation, we can see that the angular frequency ω is 1,250 rad/s.

The frequency f of the wave is related to the angular frequency by the equation f = ω / 2π.

Substituting ω = 1,250 rad/s into this equation gives f = 1,250 / 2π = 198.94 Hz.

Therefore, the frequency of the vibration of the wave is approximately 199 Hz.

A transverse periodic wave is represented by the equation z(y, t) = 1.50 cm sin(1,250 rad/s t + 10.0 m−1 y). What is the frequency of the vibration of the wave?