For a number to be divisible by 8, the last three digits of the number must be divisible by 8.

In this case, the last three digits are 92x.

The possible values of x that make 92x divisible by 8 are 0, 4, and 8.

Among these, the minimum value of x is 0.

So, the minimum value of x is 0.

Question

For a number to be divisible by 8, the last three digits of the number must be divisible by 8.

In this case, the last three digits are 92x.

The possible values of x that make 92x divisible by 8 are 0, 4, and 8.

Among these, the minimum value of x is 0.

So, the minimum value of x is 0.

Knowee AI · Accepted Answer

For a number to be divisible by 8, the last three digits of the number must be divisible by 8.

In this case, the last three digits are 92x.

The possible values of x that make 92x divisible by 8 are 0, 4, and 8.

Among these, the minimum value of x is 0.

So, the minimum value of x is 0.

A number 3013141516171892x is divisible by 8. Find the minimum value of x