educe the oxidation number of antimony in stibnite.[1]a

Stibnite is a mineral with the chemical formula Sb2S3.

Step 1: Identify the elements in the compound. Here, we have Antimony (Sb) and Sulfur (S3).

Step 2: Determine the oxidation number of the known element. In this case, we know that the oxidation state of Sulfur (S) in compounds is usually -2.

Step 3: Use the rule that the sum of the oxidation states in a neutral compound is zero.

So, if we let x be the oxidation state of Antimony (Sb), we can set up the following equation:

2x + 3(-2) = 0

Step 4: Solve for x.

2x - 6 = 0 2x = 6 x = 3

Therefore, the oxidation number of Antimony in stibnite is +3.