The oxidation number of a monatomic ion is equal to the charge of the ion. In the Ru(OH)2 2+ cation, the overall charge is +2.

However, we know that the hydroxide ion (OH-) has a charge of -1. Since there are two hydroxide ions, their total charge is -2.

In order for the overall charge of the cation to be +2, the Ru atom must have an oxidation number of +4 to counteract the -2 charge from the two hydroxide ions.

So, the Ru atom has an oxidation number of +4.

Therefore, the correct answer is C. +4.

Question

The oxidation number of a monatomic ion is equal to the charge of the ion. In the Ru(OH)2 2+ cation, the overall charge is +2.

However, we know that the hydroxide ion (OH-) has a charge of -1. Since there are two hydroxide ions, their total charge is -2.

In order for the overall charge of the cation to be +2, the Ru atom must have an oxidation number of +4 to counteract the -2 charge from the two hydroxide ions.

So, the Ru atom has an oxidation number of +4.

Therefore, the correct answer is C. +4.

Knowee AI · Accepted Answer

The oxidation number of a monatomic ion is equal to the charge of the ion. In the Ru(OH)2 2+ cation, the overall charge is +2.

However, we know that the hydroxide ion (OH-) has a charge of -1. Since there are two hydroxide ions, their total charge is -2.

In order for the overall charge of the cation to be +2, the Ru atom must have an oxidation number of +4 to counteract the -2 charge from the two hydroxide ions.

So, the Ru atom has an oxidation number of +4.

Therefore, the correct answer is C. +4.

In the Ru(OH)22+ cation, the Ru atom has an oxidation number of:A.0B.+2C.+4D.+6

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