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The common positive oxidation states for an element with the atomic number 24

Question

The common positive oxidation states for an element with the atomic number 24

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Solution

To determine the common positive oxidation states for an element with the atomic number 24, we need to identify the element first. The atomic number 24 corresponds to the element chromium (Cr) in the periodic table.

Next, we can look at the electron configuration of chromium to determine its possible oxidation states. The electron configuration of chromium is [Ar] 3d^5 4s^1.

From this electron configuration, we can see that chromium has a partially filled 3d orbital, which means it can lose or gain electrons from this orbital to form different oxidation states.

The common positive oxidation states for chromium are +2, +3, and +6.

Chromium can lose two electrons from its 4s orbital to form the +2 oxidation state, resulting in the electron configuration [Ar] 3d^4.

It can also lose three electrons from its 4s and 3d orbitals to form the +3 oxidation state, resulting in the electron configuration [Ar] 3d^3.

Lastly, chromium can lose six electrons from its 4s and 3d orbitals to form the +6 oxidation state, resulting in the electron configuration [Ar] 3d^0.

Therefore, the common positive oxidation states for chromium (atomic number 24) are +2, +3, and +6.

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