Here is a Python solution for the problem:

```python
import math

def is_square_free(n):
if n % 2 == 0:
n = n / 2
if n % 2 == 0:
return False
for i in range(3, int(math.sqrt(n)) + 1):
if n % i == 0:
n = n / i
if n % i == 0:
return False
return True

n = int(input())
if is_square_free(n):
print("Square-Free")
else:
print("Not Square-Free")
```

This program works by first checking if the number is divisible by 2 more than once. If it is, it's not square-free. Then it checks for other factors up to the square root of the number. If it finds a factor that divides the number more than once, it's not square-free.

Please note that Python does not support the `goto` statement as it is considered a bad practice and can make code hard to understand. Instead, Python encourages the use of functions and loops for control flow.

Question

Here is a Python solution for the problem:

```python
import math

def is_square_free(n):
    if n % 2 == 0:
        n = n / 2
    if n % 2 == 0:
        return False
    for i in range(3, int(math.sqrt(n)) + 1):
        if n % i == 0:
            n = n / i
            if n % i == 0:
                return False
    return True

n = int(input())
if is_square_free(n):
    print("Square-Free")
else:
    print("Not Square-Free")
```

This program works by first checking if the number is divisible by 2 more than once. If it is, it's not square-free. Then it checks for other factors up to the square root of the number. If it finds a factor that divides the number more than once, it's not square-free.

Please note that Python does not support the `goto` statement as it is considered a bad practice and can make code hard to understand. Instead, Python encourages the use of functions and loops for control flow.

Knowee AI · Accepted Answer

Here is a Python solution for the problem:

```python
import math

def is_square_free(n):
    if n % 2 == 0:
        n = n / 2
    if n % 2 == 0:
        return False
    for i in range(3, int(math.sqrt(n)) + 1):
        if n % i == 0:
            n = n / i
            if n % i == 0:
                return False
    return True

n = int(input())
if is_square_free(n):
    print("Square-Free")
else:
    print("Not Square-Free")
```

This program works by first checking if the number is divisible by 2 more than once. If it is, it's not square-free. Then it checks for other factors up to the square root of the number. If it finds a factor that divides the number more than once, it's not square-free.

Please note that Python does not support the `goto` statement as it is considered a bad practice and can make code hard to understand. Instead, Python encourages the use of functions and loops for control flow.

Question

Solution

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