Use differentials to estimate the amount of paint needed (in m3) to apply a coat of paint 0.03 cm thick to a hemispherical dome with diameter 52 m. (Round your answer to two decimal places.)

The internal and external diameters of a hollow hemispherical vessel are 20 cm and 28cm respectively. Find the cost of painting the vessel all over at 35 paise per cm².

8: One gallon of paint (volume = 3.78 × 103 cm3) coversan area of 25.0 m2. What is the thickness of the fresh painton the wall? [volume=Area×tickness].(a) 0.51 × 103 m(b) 1.51 × 10−4 m(c) 0.51 × 103 m(d) 0.51 × 10−4 m(e) 9.45 × 103 mQ9: The Andam auditorium in Dungu Campus of UDSmeasures 40.0 m × 20.0 m × 12.0 m. The density of air is1.20 kg/m3. What is the weight of air in the room in pounds?[1 lb = 4.448 N].(a) 1.13 × 104 lb(b) 2.54 × 104 lb(c) 1.13 × 105 lb(d) 2.54 × 10−4 lb(e) 1.13 × 10−5 lbQ10: Assume the equation x = A t3 + B t describes themotion of a particular object, with x having the dimensionof length and t having the dimension of time. Determine thedimensions of the constants A and B.5

Calculate the cost required to paint a container that is in the shape of a cylinder having abase radius of 10 cm and height of 15 cm. If the painting cost of the container is Rs. 3 per ?

Radius (r) of cone =  = 0.2 m    Height (h) of cone = 1 m    Slant height (l) of cone =     CSA of each cone =  = (3.14  0.2  1.02)  = 0.64056       CSA of 50 such cones = (50  0.64056)  = 32.028           Cost of painting 1  area = Rs 12    Cost of painting 32.028  area = Rs (32.028  12) = Rs 384.336         Thus, it will cost Rs 384.34 (approximately) in painting the 50 hollow cones.

1) An open cylinder tank of radius 14 cm and height 30 cm is to be painted on its exterior surfaces. Find the total surface area that needs to be painted.