Radius (r) of cone = = 0.2 m Height (h) of cone = 1 m Slant height (l) of cone = CSA of each cone = = (3.14 0.2 1.02) = 0.64056 CSA of 50 such cones = (50 0.64056) = 32.028 Cost of painting 1 area = Rs 12 Cost of painting 32.028 area = Rs (32.028 12) = Rs 384.336 Thus, it will cost Rs 384.34 (approximately) in painting the 50 hollow cones.
Question
Radius (r) of cone = = 0.2 m Height (h) of cone = 1 m Slant height (l) of cone = CSA of each cone = = (3.14 0.2 1.02) = 0.64056 CSA of 50 such cones = (50 0.64056) = 32.028 Cost of painting 1 area = Rs 12 Cost of painting 32.028 area = Rs (32.028 12) = Rs 384.336 Thus, it will cost Rs 384.34 (approximately) in painting the 50 hollow cones.
Solution
The radius (r) of the cone is 0.2 m. The height (h) of the cone is 1 m. The slant height (l) of the cone is not given.
To find the CSA of each cone, we can use the formula CSA = π * r * l, where π is approximately 3.14. Plugging in the values, we get CSA = 3.14 * 0.2 * 1.02 = 0.64056.
To find the CSA of 50 such cones, we multiply the CSA of one cone by 50, giving us 50 * 0.64056 = 32.028.
The cost of painting 1 unit of area is given as Rs 12. Therefore, the cost of painting 32.028 units of area would be 32.028 * 12 = Rs 384.336.
Therefore, it will cost approximately Rs 384.34 to paint the 50 hollow cones.
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