Time left 0:26:56 Question 12 Tries remaining: 2 Marked out of 3.00 Flag question Tips Question text A parallel plate capacitor is charged so that a total charge of +Q ends up on the positive plate, and -Q on the negative plate. The capacitor is then disconnected from rest of the circuit. Next, I push the two plates slightly closer together. Which statement is true about the electric field and the voltage difference between the plates? Question 12Answer a. The strength of the electric field decreases while the voltage difference stays the same b. The strength of the electric field stays the same while the voltage difference decreases c. The strength of the electric field stays the same while the voltage difference increases d. The strength of the electric field increases while the voltage difference stays the same e. Neither the electric field nor the voltage difference changes
Question
Time left 0:26:56 Question 12 Tries remaining: 2 Marked out of 3.00 Flag question Tips Question text A parallel plate capacitor is charged so that a total charge of +Q ends up on the positive plate, and -Q on the negative plate.
The capacitor is then disconnected from rest of the circuit. Next, I push the two plates slightly closer together. Which statement is true about the electric field and the voltage difference between the plates? Question 12Answer
a. The strength of the electric field decreases while the voltage difference stays the same
b. The strength of the electric field stays the same while the voltage difference decreases
c. The strength of the electric field stays the same while the voltage difference increases
d. The strength of the electric field increases while the voltage difference stays the same
e. Neither the electric field nor the voltage difference changes
Solution
The correct answer is b. The strength of the electric field stays the same while the voltage difference decreases.
Here's why:
The electric field (E) between the plates of a capacitor is given by E = Q/(A*ε), where Q is the charge, A is the area of one of the plates, and ε is the permittivity of free space. Since the charge Q and the area A of the plates and the permittivity of free space ε are all constant, the electric field E remains the same when the plates are pushed closer together.
The voltage difference (V) between the plates of a capacitor is given by V = E*d, where E is the electric field and d is the distance between the plates. Since the electric field E remains the same and the distance d decreases when the plates are pushed closer together, the voltage difference V decreases.
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