What is the molar concentration of Li+ ions in a 3.1 M solution of Li3PO4?
Question
What is the molar concentration of Li+ ions in a 3.1 M solution of Li3PO4?
Solution
To find the molar concentration of Li+ ions in a 3.1 M solution of Li3PO4, you need to understand that each formula unit of Li3PO4 produces three Li+ ions when it dissolves in solution.
Here are the steps to find the molar concentration:
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Identify the number of Li+ ions per formula unit of Li3PO4. In this case, there are 3 Li+ ions.
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Multiply the molarity of the Li3PO4 solution by the number of Li+ ions per formula unit.
Calculation: 3.1 M (Li3PO4) * 3 (Li+ ions/Li3PO4) = 9.3 M (Li+ ions)
So, the molar concentration of Li+ ions in a 3.1 M solution of Li3PO4 is 9.3 M.
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