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Calculate the equilibrium constant Kc for the reaction:2XY(g) ⇌2X (s) + Y2(g)When the number of moles of XY, X2, Y2 : 0.8 ,0.4 & 0.2 moles respectively, put in container of volume = 4L .

Question

Calculate the equilibrium constant Kc for the reaction:2XY(g) ⇌2X (s) + Y2(g)When the number of moles of XY, X2, Y2 : 0.8 ,0.4 & 0.2 moles respectively, put in container of volume = 4L .

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Solution

To calculate the equilibrium constant Kc for the given reaction, we need to use the formula:

Kc = ([X]^2 * [Y2]) / [XY]^2

where [X], [Y2], and [XY] represent the molar concentrations of X, Y2, and XY, respectively.

Given that the number of moles of XY, X2, and Y2 are 0.8, 0.4, and 0.2 moles, respectively, and the volume of the container is 4L, we can calculate the molar concentrations as follows:

[X] = (0.4 moles) / (4L) = 0.1 M [Y2] = (0.2 moles) / (4L) = 0.05 M [XY] = (0.8 moles) / (4L) = 0.2 M

Now, we can substitute these values into the equilibrium constant expression:

Kc = (0.1^2 * 0.05) / (0.2^2) = 0.001 / 0.04 = 0.025

Therefore, the equilibrium constant Kc for the given reaction is 0.025.

This problem has been solved

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