The freezing point depression (∆Tf) is calculated using the formula:

∆Tf = Kf * m * i

where:
- ∆Tf is the freezing point depression,
- Kf is the cryoscopic constant (for water it is 1.86 °C/m),
- m is the molality of the solution,
- i is the van't Hoff factor (number of particles the solute splits into in solution).

For most salts, i is typically 2, but it can vary. If we assume i is 2 for this problem, we can substitute the given values into the formula:

∆Tf = 1.86 °C/m * 2.25 m * 2 = 8.37 °C

The new freezing point of the solution is the original freezing point minus the freezing point depression:

New freezing point = Original freezing point - ∆Tf
New freezing point = 0 °C - 8.37 °C = -8.37 °C

None of the provided answer choices match this result. Please check the problem statement or the given answer choices.

Question

The freezing point depression (∆Tf) is calculated using the formula:

∆Tf = Kf * m * i

where:
- ∆Tf is the freezing point depression,
- Kf is the cryoscopic constant (for water it is 1.86 °C/m),
- m is the molality of the solution,
- i is the van't Hoff factor (number of particles the solute splits into in solution).

For most salts, i is typically 2, but it can vary. If we assume i is 2 for this problem, we can substitute the given values into the formula:

∆Tf = 1.86 °C/m * 2.25 m * 2 = 8.37 °C

The new freezing point of the solution is the original freezing point minus the freezing point depression:

New freezing point = Original freezing point - ∆Tf
New freezing point = 0 °C - 8.37 °C = -8.37 °C

None of the provided answer choices match this result. Please check the problem statement or the given answer choices.

Knowee AI · Accepted Answer

The freezing point depression (∆Tf) is calculated using the formula:

∆Tf = Kf * m * i

where:
- ∆Tf is the freezing point depression,
- Kf is the cryoscopic constant (for water it is 1.86 °C/m),
- m is the molality of the solution,
- i is the van't Hoff factor (number of particles the solute splits into in solution).

For most salts, i is typically 2, but it can vary. If we assume i is 2 for this problem, we can substitute the given values into the formula:

∆Tf = 1.86 °C/m * 2.25 m * 2 = 8.37 °C

The new freezing point of the solution is the original freezing point minus the freezing point depression:

New freezing point = Original freezing point - ∆Tf
New freezing point = 0 °C - 8.37 °C = -8.37 °C

None of the provided answer choices match this result. Please check the problem statement or the given answer choices.

If the molality of a salt solution is found to be 2.25 molal and the ∆T is determined to be 2.560C, what is the new freezing point of the solution?Original freezing point = 00COriginal boiling point = 1000CGroup of answer choices-2.56 0C+2.560C102.560C97.40C

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