An object of mass 10 kg kept on a table having area of contact 25 cm2 the pressure exerted by block in pascal is (g = 10m/s2)
Question
An object of mass 10 kg kept on a table having area of contact 25 cm2 the pressure exerted by block in pascal is (g = 10m/s2)
Solution
Sure, here's how you can calculate the pressure exerted by the block:
Step 1: Identify the given values.
- Mass (m) = 10 kg
- Area (A) = 25 cm^2 = 25 * 10^-4 m^2 (since 1 cm^2 = 10^-4 m^2)
- Gravitational acceleration (g) = 10 m/s^2
Step 2: Use the formula for pressure. Pressure (P) = Force (F) / Area (A)
Step 3: Calculate the force. The force exerted by the block is its weight, which is the mass times the gravitational acceleration. Force (F) = m * g = 10 kg * 10 m/s^2 = 100 N
Step 4: Substitute the values into the pressure formula. Pressure (P) = F / A = 100 N / (25 * 10^-4 m^2) = 400000 Pa
So, the pressure exerted by the block is 400000 Pascal.
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