Sarah lives on the same street as Mandy, their homes are 202m apa t. Sarah walks at 4m/stowards Mandy’s house. 12 seconds later, Mandy walks at 3m/s towards Sarah’s house. Howfar from Sarah’s house do they meet?
Question
Sarah lives on the same street as Mandy, their homes are 202m apa�t. Sarah walks at 4m/stowards Mandy’s house. 12 seconds later, Mandy walks at 3m/s towards Sarah’s house. Howfar from Sarah’s house do they meet?
Solution
Sure, let's solve this step by step:
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First, we need to calculate how far Sarah has walked before Mandy starts walking. Sarah walks at a speed of 4m/s and she starts 12 seconds before Mandy, so she walks 4m/s * 12s = 48m.
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Now, the distance between Sarah and Mandy is 202m - 48m = 154m.
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When they both start walking towards each other, they are moving at a combined speed of 4m/s + 3m/s = 7m/s.
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To find out how long it takes for them to meet, we divide the distance they need to cover by their combined speed: 154m / 7m/s = 22 seconds.
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In these 22 seconds, Sarah walks 22s * 4m/s = 88m.
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So, they meet 48m (the distance Sarah walked before Mandy started) + 88m (the distance Sarah walked while they were both moving) = 136m from Sarah's house.
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