The equivalent conductivity of 0.1 N CH3COOH at 25 °C is 80 and at infinite dilution 400. The degree of dissociation of CH3COOH is :10.10.20.5
Question
The equivalent conductivity of 0.1 N CH3COOH at 25 °C is 80 and at infinite dilution 400. The degree of dissociation of CH3COOH is :10.10.20.5
Solution
The degree of dissociation (α) can be calculated using the formula:
α = λc / λ∞
where: λc = equivalent conductivity of the solution λ∞ = equivalent conductivity at infinite dilution
Given in the problem: λc = 80 λ∞ = 400
Substituting these values into the formula:
α = 80 / 400 = 0.2
So, the degree of dissociation of CH3COOH is 0.2.
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