A can finish a work in 24 days, B in 9 days and C in 12 days. B & C start the work but are forced to leave after 3 days. The remaining work done by A in:
Question
A can finish a work in 24 days, B in 9 days and C in 12 days. B & C start the work but are forced to leave after 3 days. The remaining work done by A in:
Solution
Sure, let's solve this step by step:
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First, we need to find out the one day work of A, B, and C. A's one day work = 1/24 B's one day work = 1/9 C's one day work = 1/12
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Now, let's find out the combined one day work of B and C. B and C's one day work = B's one day work + C's one day work = 1/9 + 1/12 = 7/36
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B and C worked for 3 days, so the work done by them = 3 * (B and C's one day work) = 3 * 7/36 = 7/12
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The remaining work = 1 (total work) - 7/12 (work done by B and C) = 5/12
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Now, this remaining work is done by A. So, the time taken by A to finish the remaining work = remaining work / A's one day work = (5/12) / (1/24) = 10 days.
So, A will take 10 days to finish the remaining work.
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