Five years ago, the ratio of David and his brother’s age was 3 : 2. Ten years hence, the ratio of their ages will be 6:5. What is David’s brother’s present age?20152530
Question
Five years ago, the ratio of David and his brother’s age was 3 : 2. Ten years hence, the ratio of their ages will be 6:5. What is David’s brother’s present age?20152530
Solution
Let's denote David's age five years ago as 3x and his brother's age five years ago as 2x.
According to the problem, ten years from now, the ratio of their ages will be 6:5. This means that David's age in ten years (which is 3x + 15) to his brother's age in ten years (which is 2x + 15) is 6:5.
We can set up the equation as follows:
(3x + 15) / (2x + 15) = 6 / 5
Solving this equation, we get x = 5.
So, David's brother's age five years ago was 2x = 2*5 = 10 years.
Therefore, David's brother's present age is 10 + 5 = 15 years.
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