Tank A holds 5,034 ml of water and Tank B holds 8,827 ml of water. The water from both tanks is poured into Tank C which is empty. What is the volume of water in Tank C, rounded to the nearest hundred ml?
Question
Tank A holds 5,034 ml of water and Tank B holds 8,827 ml of water. The water from both tanks is poured into Tank C which is empty. What is the volume of water in Tank C, rounded to the nearest hundred ml?
Solution
To solve this problem, follow these steps:
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Identify the volume of water in each tank. Tank A holds 5,034 ml of water and Tank B holds 8,827 ml of water.
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Add the volumes of water from Tank A and Tank B together. This will give you the total volume of water that will be in Tank C.
5,034 ml (from Tank A) + 8,827 ml (from Tank B) = 13,861 ml
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The problem asks for the volume of water in Tank C rounded to the nearest hundred ml. To do this, look at the tens place of the total volume. If it's 5 or more, round up. If it's less than 5, round down.
In this case, the tens place is 6, which is more than 5. So, we round up.
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Therefore, the volume of water in Tank C, rounded to the nearest hundred ml, is 13,900 ml.
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