To solve this problem, we can use the lens formula and magnification formula.

1. The lens formula is 1/f = 1/v - 1/u, where f is the focal length, v is the image distance, and u is the object distance.

2. The magnification formula is m = -v/u = h'/h, where m is the magnification, h' is the image height, and h is the object height.

First, let's find the image distance using the lens formula:

1/f = 1/v - 1/u
1/30 = 1/v - 1/40

Solving for v, we get v = 120 cm. The positive sign indicates that the image is on the same side as the light being refracted, meaning it's a real image.

Next, let's find the image height using the magnification formula:

m = -v/u = h'/h
-120/40 = h'/3.0

Solving for h', we get h' = -9.0 cm. The negative sign indicates that the image is inverted.

So, the image distance is 120 cm and the image height is -9.0 cm.

Question

To solve this problem, we can use the lens formula and magnification formula.

1. The lens formula is 1/f = 1/v - 1/u, where f is the focal length, v is the image distance, and u is the object distance.

2. The magnification formula is m = -v/u = h'/h, where m is the magnification, h' is the image height, and h is the object height.

First, let's find the image distance using the lens formula:

1/f = 1/v - 1/u
1/30 = 1/v - 1/40

Solving for v, we get v = 120 cm. The positive sign indicates that the image is on the same side as the light being refracted, meaning it's a real image.

Next, let's find the image height using the magnification formula:

m = -v/u = h'/h
-120/40 = h'/3.0

Solving for h', we get h' = -9.0 cm. The negative sign indicates that the image is inverted.

So, the image distance is 120 cm and the image height is -9.0 cm.

Knowee AI · Accepted Answer

To solve this problem, we can use the lens formula and magnification formula.

1. The lens formula is 1/f = 1/v - 1/u, where f is the focal length, v is the image distance, and u is the object distance.

2. The magnification formula is m = -v/u = h'/h, where m is the magnification, h' is the image height, and h is the object height.

First, let's find the image distance using the lens formula:

1/f = 1/v - 1/u
1/30 = 1/v - 1/40

Solving for v, we get v = 120 cm. The positive sign indicates that the image is on the same side as the light being refracted, meaning it's a real image.

Next, let's find the image height using the magnification formula:

m = -v/u = h'/h
-120/40 = h'/3.0

Solving for h', we get h' = -9.0 cm. The negative sign indicates that the image is inverted.

So, the image distance is 120 cm and the image height is -9.0 cm.

A 3.0 cm tall object is placed along the principal axis of a thin convex lens of 30.0 cm focal length. If the object distance is 40.0 cm, which of the following best describes the image distance and height, respectively?

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