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An object is placed perpendicular to the principal axis of a convex lens of focal length 20 cm. The distance of the object from the lens is 30 cm. Find the magnification of the image formed.

Question

An object is placed perpendicular to the principal axis of a convex lens of focal length 20 cm. The distance of the object from the lens is 30 cm. Find the magnification of the image formed.

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Solution

Sure, let's solve this step by step.

Step 1: Identify the given values. The focal length (f) of the convex lens = +20 cm (it's positive because it's a convex lens) The object distance (u) = -30 cm (it's negative because the object is placed on the left side of the lens)

Step 2: Use the lens formula to find the image distance (v). The lens formula is 1/f = 1/v - 1/u. Rearrange the formula to solve for v: 1/v = 1/f + 1/u.

Step 3: Substitute the given values into the formula. 1/v = 1/20 + 1/(-30) 1/v = (30 - 20) / (20 * 30) 1/v = 10 / 600 1/v = 1/60

So, v = 60 cm. The positive sign indicates that the image is formed on the right side of the lens.

Step 4: Calculate the magnification (m). The magnification formula is m = -v/u.

Step 5: Substitute the values into the formula. m = -60 / -30 m = 2

So, the magnification of the image formed by the lens is 2. This means the image is twice the size of the object.

This problem has been solved

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