A sample of NOCl at 272.9 K experiences a change in volume from 4976.9 mL to 912 mL. If its new pressure is 9.1472 bar at 323.64 K, what was its original pressure in pounds per square inch?
Question
A sample of NOCl at 272.9 K experiences a change in volume from 4976.9 mL to 912 mL. If its new pressure is 9.1472 bar at 323.64 K, what was its original pressure in pounds per square inch?
Solution
To solve this problem, we will use the combined gas law which states that the ratio of the product of pressure and volume to temperature of one state is equal to the ratio of the product of pressure and volume to temperature of another state. The formula is:
P1V1/T1 = P2V2/T2
Given: V1 = 4976.9 mL V2 = 912 mL T1 = 272.9 K T2 = 323.64 K P2 = 9.1472 bar
We need to find P1. Rearranging the formula to solve for P1 gives us:
P1 = P2V2T1 / (V1*T2)
Substituting the given values:
P1 = 9.1472 bar * 912 mL * 272.9 K / (4976.9 mL * 323.64 K)
Calculate the above expression to get the value of P1 in bar.
Finally, convert the pressure from bar to pounds per square inch (psi) using the conversion factor 1 bar = 14.5038 psi.
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