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You are a network administrator working for an Internet Service Provider (ISP). The ISP has been allocated the IP address block 203.120.64.0/21. You need to allocate IP addresses to different customer segments, each requiring at least 60 host addresses. How many subnets can you create, and how many usable host addresses are available in each subnet?1.0 Marks8 subnets, 60 host addresses4 subnets, 254 host addresses 32 subnets, 30 host addresses16 subnets, 62 host addresses6 subnets, 62 host addresses

Question

You are a network administrator working for an Internet Service Provider (ISP). The ISP has been allocated the IP address block 203.120.64.0/21. You need to allocate IP addresses to different customer segments, each requiring at least 60 host addresses. How many subnets can you create, and how many usable host addresses are available in each subnet?1.0 Marks8 subnets, 60 host addresses4 subnets, 254 host addresses 32 subnets, 30 host addresses16 subnets, 62 host addresses6 subnets, 62 host addresses

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Solution

The ISP has been allocated the IP address block 203.120.64.0/21. This means that the first 21 bits of the IP address are used for the network address, leaving 11 bits for host addresses.

To calculate the number of subnets, we need to determine how many bits are needed to represent at least 60 host addresses. The formula for this is 2^n - 2 >= 60, where n is the number of bits. Solving for n, we find that n = 6 (since 2^6 - 2 = 62).

This means that we are using 6 bits for host addresses, leaving 5 bits for subnet addresses (since 11 - 6 = 5). Therefore, we can create 2^5 = 32 subnets.

The number of usable host addresses in each subnet is 2^n - 2, where n is the number of bits used for host addresses. Therefore, each subnet has 2^6 - 2 = 62 usable host addresses.

So, the answer is 32 subnets, each with 62 usable host addresses.

This problem has been solved

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