Suppose an organization is given the IP block 34.17.4.0/25, which contains 128addresses. The organization needs to divide this address block into three (03) subnetsof 32, 64 and 32 addresses. Find the subnet mask and the subnet address for eachsubnet.

To divide the IP block 34.17.4.0/25 into three subnets, we need to determine the subnet mask and subnet address for each subnet.

Step 1: Determine the subnet mask The given IP block has a subnet mask of /25, which means the first 25 bits are fixed and the remaining 7 bits can be used for subnetting.

Step 2: Determine the subnet sizes We need to divide the IP block into three subnets with sizes of 32, 64, and 32 addresses respectively.

Step 3: Determine the subnet mask for each subnet To determine the subnet mask for each subnet, we need to find the number of bits required to represent the subnet sizes.

For the first subnet with 32 addresses, we need 5 bits (2^5 = 32). So the subnet mask for this subnet will be /25 + 5 = /30.

For the second subnet with 64 addresses, we need 6 bits (2^6 = 64). So the subnet mask for this subnet will be /25 + 6 = /31.

For the third subnet with 32 addresses, we need 5 bits (2^5 = 32). So the subnet mask for this subnet will be /25 + 5 = /30.

Step 4: Determine the subnet address for each subnet To determine the subnet address for each subnet, we need to increment the network portion of the IP block by the number of bits used for subnetting.

For the first subnet with a subnet mask of /30, the subnet address will be 34.17.4.0.

For the second subnet with a subnet mask of /31, the subnet address will be 34.17.4.2.

For the third subnet with a subnet mask of /30, the subnet address will be 34.17.4.4.

In summary, the subnet mask and subnet address for each subnet are as follows:

• Subnet 1: Subnet mask = /30, Subnet address = 34.17.4.0
• Subnet 2: Subnet mask = /31, Subnet address = 34.17.4.2
• Subnet 3: Subnet mask = /30, Subnet address = 34.17.4.4