A couple with normal skin pigmentation had three children but their second born was an albino. Using letter A to represent the gene form normal skin colour, work out the genotypes of their children using a genetic cross
Question
A couple with normal skin pigmentation had three children but their second born was an albino. Using letter A to represent the gene form normal skin colour, work out the genotypes of their children using a genetic cross
Solution
Sure, here's how you can work out the genotypes of the children:
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First, we need to understand that albinism is a recessive trait. This means that a person must inherit two copies of the gene for albinism (one from each parent) to express the trait. We'll use the letter "a" to represent the gene for albinism.
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Since the couple has normal skin pigmentation, they must each carry one dominant gene for normal skin color (A) and one recessive gene for albinism (a). This makes their genotype Aa.
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When they have children, each parent passes on one of their two genes. There are four possible combinations: AA, Aa, aA, and aa.
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The only way for a child to be an albino is to inherit the "a" gene from both parents, resulting in the "aa" genotype. This means the second child's genotype is aa.
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The other two children have normal skin pigmentation, so they must have at least one "A" gene. They could either be AA or Aa. Without more information, we can't determine their exact genotypes.
So, the genotypes of the children could be AA or Aa (first child), aa (second child), and AA or Aa (third child).
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