import java.util.*; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int N = sc.nextInt(); int K = sc.nextInt(); int[] A = new int[N]; for (int i = 0; i < N; i++) { A[i] = sc.nextInt(); } Arrays.sort(A); int happyCount = 0; int j = 0; for (int i = 0; i < N; i++) { while (j < N && A[j] - A[i] < K) { j++; } if (j > i + 1) { happyCount++; } } System.out.println(happyCount); } } i need output as 5
Question
import java.util.*;
public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int N = sc.nextInt(); int K = sc.nextInt(); int[] A = new int[N]; for (int i = 0; i < N; i++) { A[i] = sc.nextInt(); } Arrays.sort(A); int happyCount = 0; int j = 0; for (int i = 0; i < N; i++) { while (j < N && A[j] - A[i] < K) { j++; } if (j > i + 1) { happyCount++; } } System.out.println(happyCount); } } i need output as 5
Solution
To get an output of 5 from this Java program, you need to provide an input that satisfies the conditions in the code. The code reads two integers N and K, and then an array of N integers. It sorts the array and then checks for pairs of numbers where the difference is less than K. If such a pair is found, it increments the happyCount.
Here's an example of an input that would give an output of 5:
7 2
1 2 3 4 5 6 7
Explanation:
The code reads N=7 and K=2. Then it reads the array [1, 2, 3, 4, 5, 6, 7]. After sorting the array (which is already sorted), it checks for pairs of numbers where the difference is less than 2. There are 5 such pairs: (1,2), (2,3), (3,4), (4,5), (5,6). So the output is 5.
Similar Questions
import java.util.Scanner;public class Test { public static void main(String[] args) { Scanner sc=new Scanner(System.in); System.out.println("Enter the number of elements in the array"); int n = sc.nextInt(); //Declare the array int arr[ ]=new int[n]; //Get the elements from user System.out.println("Enter the elements of the array"); for(int i=0;i<n;i++){ arr[i]=sc.nextInt(); } //Code to find the sum of odd elements in the array int sum=findSumOddElements(); // invoke the method System.out.println("The sum is "+); } public int findSumOddElements() { int sum=0; for(int i=0;i<;i++) { if(()!=0) { sum=sum+arr[i]; } } ; //return statement }}
public static void main(String[] args){ for (int i = 3; i <= 7; i++) {int num;if(i%2 == 0){num = 0; for (int j = 1; j <= 4; j++) { System.out.print(num); num = (num == 0)? 3 : 2; }} else {num = 1; for (int j = 1; j <= 3; j++){System.out.print(num);num = (num == 0)? 2 : 5;} } System.out.println();}}
public class main { public static int main(int N, int[] S) { int m = S.length; int[][] dp = new int[m + 1][N + 1]; for (int i = 0; i <= m; i++) { dp[i][0] = 1; } for (int i = 1; i <= m; i++) { for (int j = 1; j <= N; j++) { if (S[i - 1] <= j) { dp[i][j] = dp[i][j - S[i - 1]] + dp[i - 1][j]; } else { dp[i][j] = dp[i - 1][j]; } } } return dp[m][N]; } public static void main(String[] args) { int N = 10; int[] S = {1, 2, 3}; int result = main(N, S); System.out.println(result); } } showing errror
public class Main { public static void main(String args[]) { int arr[] = {1, 2, 3}; int m = arr.length; int n = 10; System.out.println( countWays(arr, m, n)); } static long countWays(int S[], int m, int n) { long[] table = new long[n+1]; table[0] = 1; for (int i=0; i<m; i++) for (int j=S[i]; j<=n; j++) table[j] += table[j-S[i]]; return table[n]; } } i need 14 as output
Language: Javapublic int[] sort(int[] numbers, int length)if (length < 2) {}return numbers;int mid length / 2;6int[] left = new int[id]:7int[] right new int[length mid]:9for (int i=0; i<mid; i++) {1011}1213left[i] numbers[i];for (int i-mid; i < length; i++) {INSERT MISSING CODE14}151617sort(left, mid);sort(right, length - mid);1819return merge(numbers, left, right, mid, length - mid);20}Image not displaying?Complete the sort function by replacing // INSERT MISSING CODE with the correct line of code.
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