The problem is asking for the probability that a student plays baseball given that he plays football. This is a conditional probability problem, and the formula for conditional probability is P(B|A) = P(A and B) / P(A).

Here, event A is that a student plays football and event B is that a student plays baseball.

From the problem, we know that:

P(A) = the probability that a student plays football = 18/100 = 0.18
P(A and B) = the probability that a student plays both football and baseball = 6/100 = 0.06

Substituting these values into the formula gives:

P(B|A) = P(A and B) / P(A) = 0.06 / 0.18 = 0.3333 or 33.3%

So, the probability that a student plays baseball given that he plays football is 33.3%. Therefore, the answer is C. 33.3%.

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The problem is asking for the probability that a student plays baseball given that he plays football. This is a conditional probability problem, and the formula for conditional probability is P(B|A) = P(A and B) / P(A).

Here, event A is that a student plays football and event B is that a student plays baseball.

From the problem, we know that:

P(A) = the probability that a student plays football = 18/100 = 0.18
P(A and B) = the probability that a student plays both football and baseball = 6/100 = 0.06

Substituting these values into the formula gives:

P(B|A) = P(A and B) / P(A) = 0.06 / 0.18 = 0.3333 or 33.3%

So, the probability that a student plays baseball given that he plays football is 33.3%. Therefore, the answer is C. 33.3%.

Knowee AI · Accepted Answer

The problem is asking for the probability that a student plays baseball given that he plays football. This is a conditional probability problem, and the formula for conditional probability is P(B|A) = P(A and B) / P(A).

Here, event A is that a student plays football and event B is that a student plays baseball.

From the problem, we know that:

P(A) = the probability that a student plays football = 18/100 = 0.18
P(A and B) = the probability that a student plays both football and baseball = 6/100 = 0.06

Substituting these values into the formula gives:

P(B|A) = P(A and B) / P(A) = 0.06 / 0.18 = 0.3333 or 33.3%

So, the probability that a student plays baseball given that he plays football is 33.3%. Therefore, the answer is C. 33.3%.

At a high school, 18% of the students play football and 6% of the students play football and baseball. What is the probability that a student plays baseball given that he plays football?A.1.1%B.3%C.33.3%D.10.8%SUBMITarrow_backPREVIOUS

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