In the C++ code for displaying elements in a stack, what does the loop for(i = top; i >= 0; i--) do?*1 pointa. Adds elements to the stackb. Removes elements from the stackc. Checks if the stack is emptyd. Displays elements in reverse order
Question
In the C++ code for displaying elements in a stack, what does the loop for(i = top; i >= 0; i--) do?*1 pointa. Adds elements to the stackb. Removes elements from the stackc. Checks if the stack is emptyd. Displays elements in reverse order
Solution
The loop for(i = top; i >= 0; i--) in the given C++ code is used to display elements in reverse order from the stack.
Similar Questions
What is the role of the top variable in a stack implementation?*1 pointa. It stores the value to be pushed.b. It tracks the most recently added element.c. It points to the bottom of the stack.d. It manages the display operation.
A rear pointer is used in the stack to find the last element.a.FALSEb.TRUE
What does the following pseudocode do?Stack S;while (!S.isEmpty()) { S.pop();}Checks if the stack is emptyRemoves all elements from the stackPops one element from the stackPrints all elements of the stack
What is the output of the following code snippet?void solve() { stack<int> s; s.push(1); s.push(2); s.push(3); for(int i = 1; i <= 3; i++) { cout << s.top() << “ “; s.pop(); }}
What happens if you call top() on an empty stack in C++?It returns 0It throws an exceptionIt returns a garbage valueIt returns the last element pushed onto the stack
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