The engine of a 1,462 kg car provides a forward directed force of 5,351 N.If the car accelerates at a rate of 3.2 m/s2 what is the total resistive force (wind resistance, friction, etc.) acting on the car? Express your answer in N.

Sure, let's solve this step by step:

1. First, we need to calculate the force that the car's engine is producing. According to Newton's second law of motion, Force = mass * acceleration. So, the force produced by the car's engine is 1462 kg * 3.2 m/s² = 4678.4 N.

2. The problem states that the total force acting on the car is 5351 N. This force is the sum of the force produced by the engine and the resistive force (which is acting in the opposite direction, so it's considered negative in this calculation).

3. Therefore, we can set up the equation: 4678.4 N (force from engine) - F_resistive (resistive force) = 5351 N (total force).

4. Solving for F_resistive, we get: F_resistive = 4678.4 N - 5351 N = -672.6 N.

5. The negative sign indicates that the resistive force is acting in the opposite direction of the force produced by the engine, which is what we'd expect. However, when asked for the magnitude of the force, we typically report the absolute value. So, the magnitude of the resistive force is 672.6 N.