Suppose that fish size is a heritable trait in a population of fish. The allele conferring large size (S) is incompletely dominant to the allele conferring small size (s). Heterozygotes (Ss) are of intermediate size. Suppose that a population of fish is at Hardy-Weinberg equilibrium and the frequency of the S allele is 0.9. What proportion of the next generation will be of intermediate size?The image shows two fishes of different sizes, with one fish bigger than the other.Multiple Choice0.180.90.010.090.81
Question
Suppose that fish size is a heritable trait in a population of fish. The allele conferring large size (S) is incompletely dominant to the allele conferring small size (s). Heterozygotes (Ss) are of intermediate size. Suppose that a population of fish is at Hardy-Weinberg equilibrium and the frequency of the S allele is 0.9. What proportion of the next generation will be of intermediate size?The image shows two fishes of different sizes, with one fish bigger than the other.Multiple Choice0.180.90.010.090.81
Solution
To solve this problem, we need to use the Hardy-Weinberg equilibrium equation, which is p^2 + 2pq + q^2 = 1, where p is the frequency of the dominant allele (S), q is the frequency of the recessive allele (s), 2pq is the frequency of heterozygotes (Ss), p^2 is the frequency of homozygous dominant (SS), and q^2 is the frequency of homozygous recessive (ss).
Given that the frequency of the S allele (p) is 0.9, we can find the frequency of the s allele (q) by subtracting p from 1, because p + q = 1. So, q = 1 - p = 1 - 0.9 = 0.1.
The proportion of the next generation that will be of intermediate size is represented by 2pq, which is the frequency of heterozygotes (Ss). So, 2pq = 2 * 0.9 * 0.1 = 0.18.
Therefore, the proportion of the next generation that will be of intermediate size is 0.18. So, the correct answer is 0.18.
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