To solve this problem, we first need to understand the concept of allele frequency in a population. In this case, we are dealing with a simple dominance/recessiveness trait, which means that each fish has two alleles for the color trait. One allele is inherited from the mother and the other from the father.

1. First, let's calculate the total number of alleles in the population. Since each fish has two alleles, the total number of alleles is 2 * 200 = 400.

2. Next, let's calculate the number of red alleles. Since red is recessive, all red fish must have two red alleles. So, the number of red alleles is 2 * 18 = 36.

3. Now, let's calculate the number of blue fish that are heterozygous. Heterozygous means that they have one blue allele (dominant) and one red allele (recessive). So, the number of red alleles in heterozygous blue fish is 1 * 84 = 84.

4. Add the number of red alleles from red fish and heterozygous blue fish to get the total number of red alleles in the population. So, 36 + 84 = 120.

5. Finally, calculate the frequency of the red allele by dividing the total number of red alleles by the total number of alleles. So, 120 / 400 = 0.30.

So, the frequency of the red allele in the population is 0.30.

Question

To solve this problem, we first need to understand the concept of allele frequency in a population. In this case, we are dealing with a simple dominance/recessiveness trait, which means that each fish has two alleles for the color trait. One allele is inherited from the mother and the other from the father.

1. First, let's calculate the total number of alleles in the population. Since each fish has two alleles, the total number of alleles is 2 * 200 = 400.

2. Next, let's calculate the number of red alleles. Since red is recessive, all red fish must have two red alleles. So, the number of red alleles is 2 * 18 = 36.

3. Now, let's calculate the number of blue fish that are heterozygous. Heterozygous means that they have one blue allele (dominant) and one red allele (recessive). So, the number of red alleles in heterozygous blue fish is 1 * 84 = 84.

4. Add the number of red alleles from red fish and heterozygous blue fish to get the total number of red alleles in the population. So, 36 + 84 = 120.

5. Finally, calculate the frequency of the red allele by dividing the total number of red alleles by the total number of alleles. So, 120 / 400 = 0.30.

So, the frequency of the red allele in the population is 0.30.

Knowee AI · Accepted Answer

To solve this problem, we first need to understand the concept of allele frequency in a population. In this case, we are dealing with a simple dominance/recessiveness trait, which means that each fish has two alleles for the color trait. One allele is inherited from the mother and the other from the father.

1. First, let's calculate the total number of alleles in the population. Since each fish has two alleles, the total number of alleles is 2 * 200 = 400.

2. Next, let's calculate the number of red alleles. Since red is recessive, all red fish must have two red alleles. So, the number of red alleles is 2 * 18 = 36.

3. Now, let's calculate the number of blue fish that are heterozygous. Heterozygous means that they have one blue allele (dominant) and one red allele (recessive). So, the number of red alleles in heterozygous blue fish is 1 * 84 = 84.

4. Add the number of red alleles from red fish and heterozygous blue fish to get the total number of red alleles in the population. So, 36 + 84 = 120.

5. Finally, calculate the frequency of the red allele by dividing the total number of red alleles by the total number of alleles. So, 120 / 400 = 0.30.

So, the frequency of the red allele in the population is 0.30.

In a population of 200 fish, 182 fish are blue, and 18 fish are red. 84 of the 182 blue fish are heterozygous for the color trait. What is the frequency of the red allele in the population? (Assume simple dominance/recessiveness of the color allele.)Multiple Choice0.30.70.510.60.09

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