Select the correct answerA stack is implemented with an array of 'A [0..N - 1]' and a varlable 'pos'. The push and pop operations are defined by the following code.push(x) A[pos] ← X pos ← pos - 1end pushpop( ) pos ← pos + 1 return A[pos]end popWhich of the following will initialize an empty stack with capacity N for the above Implementation?Optionspos ← −1pos ← 1pos ← N−1pos
Question
Select the correct answerA stack is implemented with an array of 'A [0..N - 1]' and a varlable 'pos'. The push and pop operations are defined by the following code.push(x) A[pos] ← X pos ← pos - 1end pushpop( ) pos ← pos + 1 return A[pos]end popWhich of the following will initialize an empty stack with capacity N for the above Implementation?Optionspos ← −1pos ← 1pos ← N−1pos
Solution
The correct answer is "pos ← N−1". This is because the stack is implemented with an array of 'A [0..N - 1]' and the variable 'pos' is used to keep track of the top of the stack. When a new element is pushed onto the stack, 'pos' is decremented (pos ← pos - 1). Therefore, to initialize an empty stack with capacity N, 'pos' should be set to N-1, which is the last index of the array. This means that the first element will be inserted at the end of the array, and subsequent elements will fill the array from end to start.
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