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Consider the following operation performed on a stack of size 5.Push(1);Pop();Push(2);Push(3);Pop();Push(4);Pop();Pop();Push(5);After the completion of all operation, the no of element present on stack are

Question

Consider the following operation performed on a stack of size 5.Push(1);Pop();Push(2);Push(3);Pop();Push(4);Pop();Pop();Push(5);After the completion of all operation, the no of element present on stack are

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Solution

Let's go through the operations one by one:

  1. Push(1): This operation adds the element '1' to the stack. The stack now contains one element.

  2. Pop(): This operation removes the last element added to the stack. The stack is now empty.

  3. Push(2): This operation adds the element '2' to the stack. The stack now contains one element.

  4. Push(3): This operation adds the element '3' to the stack. The stack now contains two elements.

  5. Pop(): This operation removes the last element added to the stack, which is '3'. The stack now contains one element.

  6. Push(4): This operation adds the element '4' to the stack. The stack now contains two elements.

  7. Pop(): This operation removes the last element added to the stack, which is '4'. The stack now contains one element.

  8. Pop(): This operation removes the last element added to the stack, which is '2'. The stack is now empty.

  9. Push(5): This operation adds the element '5' to the stack. The stack now contains one element.

So, after the completion of all operations, the number of elements present on the stack is 1.

This problem has been solved

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