The average of three numbers is 32. The ratio between first number and the second number is 27:10. If the third number is 2 more than the second number, what is the sum of first and second numbers?

Sure, let's solve this step by step:

Step 1: We know that the average of three numbers is 32. So, the sum of these three numbers is 32 * 3 = 96.

Step 2: The ratio between the first number and the second number is 27:10. Let's assume the first number as 27x and the second number as 10x.

Step 3: It's given that the third number is 2 more than the second number. So, the third number is 10x + 2.

Step 4: Now, we know that the sum of these three numbers is 96. So, we can set up the equation as follows: 27x + 10x + 10x + 2 = 96.

Step 5: Simplifying the equation, we get 47x + 2 = 96.

Step 6: Subtract 2 from both sides, we get 47x = 94.

Step 7: Divide both sides by 47, we get x = 2.

Step 8: Substituting x = 2 in 27x and 10x, we get the first number as 54 and the second number as 20.

So, the sum of the first and second numbers is 54 + 20 = 74.

To solve this problem, we need to follow these steps:

1. We know that the average of three numbers is 32. So, the sum of these three numbers is 32 * 3 = 96.

2. The ratio between the first number and the second number is 27:10. Let's assume the first number is 27x and the second number is 10x.

3. The third number is 2 more than the second number. So, the third number is 10x + 2.

4. Now, we know that the sum of these three numbers is 96. So, we can set up the equation: 27x + 10x + 10x + 2 = 96.

5. Simplifying the equation, we get 47x + 2 = 96.

6. Subtract 2 from both sides, we get 47x = 94.

7. Divide both sides by 47, we get x = 2.

8. Now, we can find the first and second numbers. The first number is 27x = 27 * 2 = 54 and the second number is 10x = 10 * 2 = 20.

9. So, the sum of the first and second numbers is 54 + 20 = 74.