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Of the three numbers, the average of the first and the second is greater than the average of the second and the third by 37. What is the difference between the first and the third of the three numbers? Options :705463none of these

Question

Of the three numbers, the average of the first and the second is greater than the average of the second and the third by 37. What is the difference between the first and the third of the three numbers? Options :705463none of these

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Solution

The problem can be solved by using the formula for the average of two numbers and the given conditions.

The average of two numbers is the sum of the numbers divided by 2.

Let's denote the three numbers as A, B, and C.

According to the problem, the average of A and B is greater than the average of B and C by 37.

This can be written as:

(A + B)/2 = (B + C)/2 + 37

Solving this equation for A - C (the difference between the first and the third number) gives:

A - C = 2 * 37 = 74

So, the difference between the first and the third of the three numbers is 74.

Therefore, the answer is "none of these" from the given options.

This problem has been solved

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