Two light sources are used in a photoelectric experiment to determine the work function for a particular metal surface.When green light from a mercury lamp (𝜆 = 546.1 nm) is used, a stopping potential of 0.8 V reduces the photocurrent to zero.

Two light sources are used in a photoelectric experiment to determine the work function for a particular metal surface.When green light from a mercury lamp (𝜆 = 546.1 nm) is used, a stopping potential of 0.8 V reduces the photocurrent to zero.Based on this measurement, what is the work function for this metal?  Express your answer in units of eV.Answer for part 1What stopping potential would be observed when using light from a red lamp with wavelength 𝜆 = 647 nm?

Light of wavelength 180nm strikes a metal target and photoelectrons are emitted. It is noticed that the photocurrent drops to zero at stopping potential of 0.8 V. The work function of the metal surface is

From the photoelectric effect experiment, following observations are made. Identify which of these are correctA. The stopping potential depends only on the work function of the metal.B. The saturation current increases as the intensity of incident light increases.C. The maximum kinetic energy of a photo electron depends on the intensity of the incident light.D. Photoelectric effect can be explained using wave theory of light.Choose the correct answer from the options given below:B, C onlyA, C, D onlyB onlyA, B, D only

The work function of a metal is 31 eV. To eject a photoelectron of zero velocity from the surface of the metal the wavelength of incident light should be above

Light of wavelength 390 nm is directed at a metal electrode. To find the energy of electrons ejected, an opposing potential difference is established between it and another electrode. The current of photoelectrons from one to the other is stopped completely when the potential difference is 1.10 V. Determine i) the work function of the metal and ii) the maximum wavelength of light that can eject electrons from this metal. (amplify the signal?)