Light of wavelength 390 nm is directed at a metal electrode. To find the energy of electrons ejected, an opposing potential difference is established between it and another electrode. The current of photoelectrons from one to the other is stopped completely when the potential difference is 1.10 V. Determine i) the work function of the metal and ii) the maximum wavelength of light that can eject electrons from this metal. (amplify the signal?)

To find the energy of electrons ejected, we need to determine the work function of the metal and the maximum wavelength of light that can eject electrons from it.

i) The work function of the metal can be calculated using the equation:

Work function = e * V

where e is the elementary charge (1.6 x 10^-19 C) and V is the potential difference (1.10 V) at which the current of photoelectrons is stopped completely.

Substituting the values, we get:

Work function = (1.6 x 10^-19 C) * (1.10 V)

Work function = 1.76 x 10^-19 J

Therefore, the work function of the metal is 1.76 x 10^-19 J.

ii) The maximum wavelength of light that can eject electrons from the metal can be determined using the equation:

Energy of photon = Work function + Kinetic energy of ejected electron

The energy of a photon can be calculated using the equation:

Energy of photon = (hc) / λ

where h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength of light.

Setting the energy of the photon equal to the work function, we have:

(hc) / λ = 1.76 x 10^-19 J

Rearranging the equation, we can solve for the maximum wavelength:

λ = (hc) / (1.76 x 10^-19 J)

Substituting the values, we get:

λ = (6.626 x 10^-34 J·s * 3.00 x 10^8 m/s) / (1.76 x 10^-19 J)

λ = 1.19 x 10^-7 m

Therefore, the maximum wavelength of light that can eject electrons from this metal is 1.19 x 10^-7 m.