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The high throughput screening assay was carried out by analyzing fluorescence emission spectra at 584 nm. What is the energy of photons at this wavelength? (Note: Planck’s Constant = 6.6 × 10-34 m2kg/s)A.3.4 × 10-19 JB.1.3 × 10-48 JC.2.7 × 1035 JD.3.9 × 10-31 J

Question

The high throughput screening assay was carried out by analyzing fluorescence emission spectra at 584 nm. What is the energy of photons at this wavelength? (Note: Planck’s Constant = 6.6 × 10-34 m2kg/s)A.3.4 × 10-19 JB.1.3 × 10-48 JC.2.7 × 1035 JD.3.9 × 10-31 J

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Solution

The energy of a photon can be calculated using the formula:

E = hc/λ

where: E is the energy of the photon, h is Planck's constant (6.6 × 10^-34 m^2kg/s), c is the speed of light (approximately 3 × 10^8 m/s), and λ is the wavelength.

Given that the wavelength is 584 nm, we first need to convert this to meters:

1 nm = 10^-9 m, so 584 nm = 584 × 10^-9 m = 5.84 × 10^-7 m.

Substituting these values into the formula gives:

E = (6.6 × 10^-34 m^2kg/s × 3 × 10^8 m/s) / 5.84 × 10^-7 m = 3.4 × 10^-19 J

So, the energy of photons at this wavelength is 3.4 × 10^-19 J. Therefore, the correct answer is A. 3.4 × 10^-19 J.

This problem has been solved

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