Given two numbers N and R, find the value of NCR.Input FormatThe first and only line of input contains integers N and R.Output FormatPrint the value of NCRConstraints1 <= N <= 101 <= R <= 10ExampleInput5 3Output10

if nC12 = nC8, find the value of n

Problem Statement:Accept two integers and print quotient  with 16 decimal places and print the remainder in next line.Input Format:Accept two integers as inputOutput Format:Print Quotient and Remainder as follows:The quotient when NUM1 is divided by NUM2 is QUOTIENT_VALThe remainder when NUM1 is divided by NUM2 is REM_VALConstraints:1<=N1,N2<=10^15Sample Input 1:54 65Sample Output 1:The quotient when 54 is divided by 65 is 0.8307692307692308The remainder when 54 is divided by 65 is 54Sample Input 2:23 78Sample Output 2:The quotient when 23 is divided by 78 is 0.2948717948717949The remainder when 23 is divided by 78 is 23

You are given two integers 'n' and 'r' and a prime number 'p'. Your task is to find (nCr) % p where nCr can be calculated as n! / (r! * (n - r)!).Note :N! = 1 * 2 * 3 *... NInput format :The first line of input contains a single integer 'T', representing the number of test cases. The first line of each test case contains three space-separated integers 'n', 'r', and 'p'.Output format :For each test case, print a single line containing an integer representing the value of (nCr) % p.The output of each test case will be printed on a separate line.Note:You don't need to input or print anything, it has already been taken care of. Just implement the given function.Constraints :1 <= T <= 5 1 <= n, r, p <= 5 * 10 ^ 2p is prime number.Time limit: 1 sec.Sample Input 1 :2 5 2 114 3 13Sample Output 1 :104Explanation for Sample Output 1:In test case 1, n = 5, r = 2, and p = 11n C r = 5 C 2 = (5 * 4) / (2!) = 10n C r % p = 10 % 11 = 10. So the answer will be 10.In test case 2,n = 4, r = 3, and p = 13 n C r = 4 C 3 = 4 C 1 = 4 n C r % p = 4 % 13 = 4. So the answer will be 4.Sample Input 2 :25 2 1710 2 13Sample Output 2 :106

You are given a line «n#m», where «n» and «m» are digits, and «#» is a sign «+» or «-». Print the value of the given expression.InputThe only given line has a string in form «n#m», where «n» and «m» are digits (from 0 to 9), and «#» is a sign «+» or «-».OutputPrint the value of the given expression.ExamplesinputCopy1-5outputCopy-4

Solve for the indicated variable. Include all of your work in your answer. Submit your solution.C = 2r; for r