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You are given a line «n#m», where «n» and «m» are digits, and «#» is a sign «+» or «-». Print the value of the given expression.InputThe only given line has a string in form «n#m», where «n» and «m» are digits (from 0 to 9), and «#» is a sign «+» or «-».OutputPrint the value of the given expression.ExamplesinputCopy1-5outputCopy-4

Question

You are given a line «n#m», where «n» and «m» are digits, and «#» is a sign «+» or «-». Print the value of the given expression.InputThe only given line has a string in form «n#m», where «n» and «m» are digits (from 0 to 9), and «#» is a sign «+» or «-».OutputPrint the value of the given expression.ExamplesinputCopy1-5outputCopy-4

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Solution

Here is a step-by-step solution to the problem:

  1. First, you need to parse the input string. This can be done by using the split() function in Python. This function splits a string into a list where each word is a list item. In this case, you can split the string by the # character.

  2. After splitting the string, you will have a list with two elements. The first element is n and the second element is m. You need to convert these elements from string to integer. This can be done by using the int() function in Python.

  3. Now, you need to check the sign of the operation. This can be done by checking the character at the index 1 of the input string. If the character is +, then you need to add n and m. If the character is -, then you need to subtract m from n.

  4. Finally, you need to print the result of the operation.

Here is a Python code that solves the problem:

# read the input string
s = input()

# split the string by the '#' character
n, m = s.split('#')

# convert n and m from string to integer
n = int(n)
m = int(m)

# check the sign of the operation and perform the operation
if s[1] == '+':
    result = n + m
else:
    result = n - m

# print the result
print(result)

This code reads the input string, splits it by the # character, converts n and m from string to integer, checks the sign of the operation, performs the operation, and prints the result.

This problem has been solved

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