Suppose that the handedness of the last 15 U.S. presidents is as follows:(i) 40% were left-handed (L)(ii) 47% were democrats (D)(iii) If a president is left-handed, there is a 13% chance that the president is a Democrat.What is the probability that a randomly chosen U.S. president is left-handed and a democrat? 0.40 * 0.47 = 0.1880 0.40 * 0.13 = 0.0520 0.47 * 0.13 = 0.0611 0.40/0.47 = 0.8510 0.40/0.13 = 3.0769 0.47/0.13 = 3.6154
Question
Suppose that the handedness of the last 15 U.S. presidents is as follows:(i) 40% were left-handed (L)(ii) 47% were democrats (D)(iii) If a president is left-handed, there is a 13% chance that the president is a Democrat.What is the probability that a randomly chosen U.S. president is left-handed and a democrat? 0.40 * 0.47 = 0.1880 0.40 * 0.13 = 0.0520 0.47 * 0.13 = 0.0611 0.40/0.47 = 0.8510 0.40/0.13 = 3.0769 0.47/0.13 = 3.6154
Solution
The question is asking for the probability that a randomly chosen U.S. president is both left-handed and a Democrat.
Given that:
- 40% of the presidents were left-handed (L)
- 47% of the presidents were Democrats (D)
- If a president is left-handed, there is a 13% chance that the president is a Democrat
The probability that a president is both left-handed and a Democrat is given by the probability of a president being left-handed (0.40) multiplied by the conditional probability of a left-handed president being a Democrat (0.13).
So, the probability is 0.40 * 0.13 = 0.052 or 5.2%.
This means that there is a 5.2% chance that a randomly chosen U.S. president is both left-handed and a Democrat.
Similar Questions
Suppose that the handedness of the last fifteen U.S. presidents is as follows:40% were left-handed (L)47% were Democrats (D)If a president is left-handed, there is a 13% chance that the president is a Democrat.Based on this information on the last fifteen U.S. presidents, is “being left-handed” independent of “being a Democrat”? No, since 0.47 is not equal to 0.13. No, since 0.40 is not equal to 0.13. Yes, since 0.40 * 0.47 is not equal to 0.13. Yes, since 0.47 is not equal to 0.13.
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