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a block of mass 0350 kg is towed up an inclined plane tilted at an angle of 25.0° to thehorizontal. The block is moved from point A to point B, a distance of 1.75 m, by a force of 22.5 N. What isthe block's change in gravitational potential energy when the it arrives at point B?a. 5.44 J c. 22.5 .1b. 12:9.1 d. 39.4J

Question

a block of mass 0350 kg is towed up an inclined plane tilted at an angle of 25.0° to thehorizontal. The block is moved from point A to point B, a distance of 1.75 m, by a force of 22.5 N. What isthe block's change in gravitational potential energy when the it arrives at point B?a. 5.44 J c. 22.5 .1b. 12:9.1 d. 39.4J

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Solution 1

The change in gravitational potential energy can be calculated using the formula:

ΔPE = mgh

where: m is the mass of the block, g is the acceleration due to gravity, and h is the height the block is lifted.

The height can be calculated using the formula for the sine of an angle in a right triangle:

sin(θ) = h/d

where: θ is the angle of the incline, and d is the distance the block is moved.

First, we need to calculate the height. We know that the distance d is 1.75 m and the angle θ is 25.0°. So,

h = d*sin(θ) h = 1.75 m * sin(25.0°) h ≈ 0.74 m

Now we can calculate the change in potential energy. We know that the mass m is 0.350 kg and the acceleration due to gravity g is approximately 9.8 m/s². So,

ΔPE = mgh ΔPE = 0.350 kg * 9.8 m/s² * 0.74 m ΔPE ≈ 2.54 J

So, the block's change in gravitational potential energy when it arrives at point B is approximately 2.54 J. However, this answer is not in the provided options. Please check the given values and options.

This problem has been solved

Solution 2

The change in gravitational potential energy can be calculated using the formula:

ΔPE = m * g * h

where: m is the mass of the object, g is the acceleration due to gravity, and h is the height.

First, we need to find the height (h). We can do this by using the sine of the angle of the incline and the distance the block was moved.

h = 1.75m * sin(25.0°)

Once we have the height, we can substitute the values into the formula:

ΔPE = 0.350kg * 9.8m/s² * h

Let's calculate it step by step:

  1. Calculate the height: h = 1.75m * sin(25.0°) = 0.74m

  2. Substitute the values into the formula to find the change in potential energy: ΔPE = 0.350kg * 9.8m/s² * 0.74m = 2.53J

So, the block's change in gravitational potential energy when it arrives at point B is approximately 2.53J. However, this answer is not in the provided options. Please check the question or the provided options again.

This problem has been solved

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