Which of the following compound can exist in meso form – 1, 2–Dichlorobutane2, 3–Dichloropentane  2, 3–Dichloro butane1, 2–Dichloropentane

The compound that can exist in meso form among the given options is 2,3-Dichlorobutane.

Here's why:

A meso compound is a molecule with multiple stereocenters that is superimposable on its mirror image. In other words, it's a molecule that has chiral centers but is not chiral itself.

For a compound to have a meso form, it must have two or more chiral centers and a plane of symmetry.

1,2-Dichlorobutane and 1,2-Dichloropentane can't have a meso form because they only have one chiral center.

2,3-Dichloropentane can't have a meso form because it doesn't have a plane of symmetry.

2,3-Dichlorobutane, however, has two chiral centers and a plane of symmetry, so it can exist in a meso form.