what is the 8th term from the last term of the ap 11,15,19,23........107?

The given sequence is an arithmetic progression (AP) with first term (a) as 11 and common difference (d) as 4. The last term (l) is given as 107.

The nth term of an AP is given by the formula: a + (n-1)d

First, we need to find the total number of terms (n) in the given AP. We can use the formula for the nth term of an AP, which is:

l = a + (n-1)d

Substituting the given values, we get:

107 = 11 + (n-1)4

Solving this equation, we get:

96 = (n-1)4

n-1 = 96/4

n-1 = 24

n = 24 + 1

n = 25

So, there are 25 terms in the given AP.

The 8th term from the last term would be the (25 - 8 + 1)th term from the start, which is the 18th term.

We can find the 18th term using the formula for the nth term of an AP:

T18 = a + (18-1)d

T18 = 11 + 17*4

T18 = 11 + 68

T18 = 79

So, the 8th term from the last term of the AP is 79.