Oxidation state of chromium in chromite ore is______

The oxidation state of chromium in chromite ore (FeCr2O4) is +3.

Here's the step-by-step explanation:

1. Write down the formula for chromite ore: FeCr2O4

2. Assign oxidation numbers based on the rules of oxidation states. Oxygen usually has an oxidation state of -2 in compounds. Iron (Fe) usually has an oxidation state of +2 or +3.

3. Set up an equation to solve for the oxidation state of chromium. Let's denote the oxidation state of chromium as x.

4. According to the formula, there are two chromium atoms, so the total oxidation state contributed by chromium is 2x.

5. The total oxidation state of a neutral compound is zero. So, we can set up the equation as follows:

   +2 (from Fe) + 2x (from Cr) - 8 (from 4 O atoms) = 0

6. Solve the equation for x:

   2x = 8 - 2 2x = 6 x = +3

So, the oxidation state of chromium in chromite ore is +3.

The oxidation state of chromium in chromite ore (FeCr2O4) is +3.

Here's the step-by-step explanation:

1. Write down the formula for chromite ore: FeCr2O4

2. Assign oxidation numbers based on the rules of oxidation states. Oxygen usually has an oxidation state of -2 in compounds. Iron (Fe) usually has an oxidation state of +2 or +3.

3. Set up an equation to solve for the unknown oxidation state of chromium (Cr). Let's denote the oxidation state of chromium as x.

4. According to the oxidation state rules, the sum of the oxidation states in a neutral compound is zero. So, we have:

   Fe (+2) + 2Cr (x) + 4O (-2) = 0

5. Simplify the equation:

   2 + 2x - 8 = 0

6. Solve for x:

   2x = 6 x = +3

So, the oxidation state of chromium in chromite ore is +3.