The resistance of a piece of wire is 12 Ω. It is bent to form an equilateral triangle. What is theequivalent resistance between any two corners of the triangles?A) 1.3 Ω C) 4.0 ΩB) 2.0 Ω D) 2.7 Ω2016Q.16 If the length, width and separation between the plates of a parallel plate capacitor is doubledthen its capacitance becomes:A) Double C) Four-timesB) Half D) Eight-timesQ.17 Resistance between two opposite faces of square thin film of area 1 mm2 having thickness of1 μm if resistivity of material is 10 6 Ω will be:A) 1000 Ω C) 1 ΩB) 100 Ω D) 10 ΩQ.18 Total resistance between ‘A’ and ‘B’ in the given circuit is:5 ΩA5 Ω 5 Ω 5 ΩBA) 5.6 Ω C) 0.33 ΩB) 3.33 Ω D) 6.6 ΩA B6 Ω 6 Ω 6 Ω
Question
The resistance of a piece of wire is 12 Ω. It is bent to form an equilateral triangle. What is theequivalent resistance between any two corners of the triangles?A) 1.3 Ω C) 4.0 ΩB) 2.0 Ω D) 2.7 Ω2016Q.16 If the length, width and separation between the plates of a parallel plate capacitor is doubledthen its capacitance becomes:A) Double C) Four-timesB) Half D) Eight-timesQ.17 Resistance between two opposite faces of square thin film of area 1 mm2 having thickness of1 μm if resistivity of material is 10 6 Ω will be:A) 1000 Ω C) 1 ΩB) 100 Ω D) 10 ΩQ.18 Total resistance between ‘A’ and ‘B’ in the given circuit is:5 ΩA5 Ω 5 Ω 5 ΩBA) 5.6 Ω C) 0.33 ΩB) 3.33 Ω D) 6.6 ΩA B6 Ω 6 Ω 6 Ω
Solution
Claro, aquí tienes las respuestas paso a paso:
Pregunta 1: La resistencia de un alambre es de 12 Ω. Se dobla para formar un triángulo equilátero. ¿Cuál es la resistencia equivalente entre dos esquinas del triángulo?
- La longitud total del alambre es 12 Ω.
- Al formar un triángulo equilátero, cada lado del triángulo tendrá una resistencia de 12 Ω / 3 = 4 Ω.
- Para encontrar la resistencia equivalente entre dos esquinas del triángulo, consideramos dos resistencias en paralelo (los dos lados del triángulo) y una en serie (el tercer lado).
- La resistencia
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