What will be the output of the following C code?#include<stdio.h>int main(){ int a=0, b=1, c=2; *((a+1 == 1) ? &b : &a) = a ? b : c; printf("%d, %d, %d\n", a, b, c); return 0;} Ops:   A. 0,2,2    B. 2,2,2    C. 0,1,2    D. 1,1,2

The output of the given C code will be 0,2,2.

Here's the step by step explanation:

1. In the expression *((a+1 == 1) ? &b : &a) = a ? b : c;, first (a+1 == 1) is evaluated. Since a is 0, a+1 equals 1, so (a+1 == 1) is true.

2. Because the condition is true, &b (the address of b) is selected by the ternary operator ? :.

3. On the right side of the = operator, a ? b : c is evaluated. Since a is 0 (which is considered false in C), c is selected by the ternary operator.

4. Therefore, c (which is 2) is assigned to the location pointed by &b, which means b is now 2.

5. Finally, printf("%d, %d, %d\n", a, b, c); prints the values of a, b, and c, which are 0, 2, and 2 respectively.

So, the correct answer is A. 0,2,2.