It is known that 4% of children carry a certain virus, but a leading health researcher suspects that the percentage is actually higher. Which of the following provides the most convincing evidence to support the researcher’s suspicion? Out of 20 randomly chosen children, 1 child carries the virus. Out of 60 randomly chosen children, 3 children carry the virus. Out of 5,000 randomly chosen children, 250 children carry the virus. Out of 5,000 randomly chosen children, 210 children carry the virus.
Question
It is known that 4% of children carry a certain virus, but a leading health researcher suspects that the percentage is actually higher. Which of the following provides the most convincing evidence to support the researcher’s suspicion? Out of 20 randomly chosen children, 1 child carries the virus. Out of 60 randomly chosen children, 3 children carry the virus. Out of 5,000 randomly chosen children, 250 children carry the virus. Out of 5,000 randomly chosen children, 210 children carry the virus.
Solution
To determine which scenario provides the most convincing evidence that the percentage of children carrying the virus is higher than 4%, we need to calculate the percentage of children carrying the virus in each scenario and compare it to 4%.
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In the first scenario, 1 out of 20 children carry the virus. This is 5% (1/20 * 100), which is higher than 4%.
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In the second scenario, 3 out of 60 children carry the virus. This is 5% (3/60 * 100), which is also higher than 4%.
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In the third scenario, 250 out of 5,000 children carry the virus. This is 5% (250/5000 * 100), which is higher than 4%.
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In the fourth scenario, 210 out of 5,000 children carry the virus. This is 4.2% (210/5000 * 100), which is slightly higher than 4%.
Therefore, the third scenario, where 250 out of 5,000 children carry the virus (5%), provides the most convincing evidence to support the researcher’s suspicion that the percentage of children carrying the virus is higher than 4%.
Similar Questions
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