If f(x)=𝑥ସ − 4𝑥ଷ + 3𝑥ଶ − 2𝑥 + 1, then find whether f(0) X f(-1)=f(2)

Sure, let's solve this step by step.

Step 1: Find f(0) Substitute x = 0 in the function f(x)=𝑥ସ − 4𝑥ଷ + 3𝑥ଶ − 2𝑥 + 1 f(0) = 0 - 0 + 0 - 0 + 1 = 1

Step 2: Find f(-1) Substitute x = -1 in the function f(x)=𝑥ସ − 4𝑥ଷ + 3𝑥ଶ − 2𝑥 + 1 f(-1) = -1 - 4*(-1) + 3*(-1) - 2*(-1) + 1 = -1 + 4 - 3 + 2 + 1 = 3

Step 3: Find f(2) Substitute x = 2 in the function f(x)=𝑥ସ − 4𝑥ଷ + 3𝑥ଶ − 2𝑥 + 1 f(2) = 2 - 42 + 32 - 2*2 + 1 = 2 - 8 + 6 - 4 + 1 = -3

Step 4: Check if f(0) X f(-1) = f(2) 1 * 3 = -3 This is not true. Therefore, f(0) X f(-1) is not equal to f(2).