In a circular queue implementation using an array, which of the following conditions correctly identifies an overflow situation?A(rear + 1) % capacity == frontBrear == frontC(front - 1) % capacity == frontD(rear - 1) % capacity == front
Question
In a circular queue implementation using an array, which of the following conditions correctly identifies an overflow situation?A(rear + 1) % capacity == frontBrear == frontC(front - 1) % capacity == frontD(rear - 1) % capacity == front
Solution
The correct condition that identifies an overflow situation in a circular queue implementation using an array is A: (rear + 1) % capacity == front.
Here's why:
In a circular queue, we keep track of two pointers or indices, front and rear. The front index points to the start of the queue, while the rear index points to the end of the queue.
When we enqueue an element, we add it at the position pointed to by 'rear' and then increment the 'rear' index. If the queue is full, we cannot add a new element even if there are empty spaces in the array. This is because we cannot increment 'rear' as it would then point to the 'front' of the queue, causing an overflow.
So, the condition for overflow is when the next position of 'rear' is the 'front' of the queue. We calculate the next position as (rear + 1) % capacity. If this is equal to 'front', it means the queue is full.
Therefore, the correct answer is A: (rear + 1) % capacity == front.
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